Comments on: What percentage of the antacid is active ingredient? http://www.theperfectsystem.net/1-perfect-system/what-percentage-of-the-antacid-is-active-ingredient Wed, 14 Jul 2010 10:40:59 -0400 http://wordpress.org/?v=2.8.4 hourly 1 By: steve_geo1 http://www.theperfectsystem.net/1-perfect-system/what-percentage-of-the-antacid-is-active-ingredient/comment-page-1#comment-4408 steve_geo1 Sat, 30 Jan 2010 20:53:59 +0000 http://www.theperfectsystem.net/1-perfect-system/what-percentage-of-the-antacid-is-active-ingredient#comment-4408 Ca(HCO3)2 + 2HCl ===> CaCl2 + 2CO2 + 2H2O Atomic weights: Ca=40 H=1 C=12 O=16 Ca(HCO3)2=162 Let the antacid be called A. Let Ca(HCO3)2, the active ingredient, be called CB. 25.00C=298.00K 88.15mLCO2/0.433gA x 273K/298K x 1molCO2/22,400mLCO2 x 1molCB/2molCO2 x 162gCB/1molCB x 100% = 67.4% CB<br><b>References : </b><br> Ca(HCO3)2 + 2HCl ===> CaCl2 + 2CO2 + 2H2O

Atomic weights: Ca=40 H=1 C=12 O=16 Ca(HCO3)2=162

Let the antacid be called A. Let Ca(HCO3)2, the active ingredient, be called CB. 25.00C=298.00K

88.15mLCO2/0.433gA x 273K/298K x 1molCO2/22,400mLCO2 x 1molCB/2molCO2 x 162gCB/1molCB x 100% = 67.4% CB
References :

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